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3 years ago

The length of an object in feet is equal to 3 times it's length in yards.

Mathematics

1 answer:

qwelly [4]3 years ago

5 0

Answer:

Step-by-step explanation:

3 times X is equal to 36.

X is the number were going to solve for, and since you need 3 groups of 12 to solve for 36, it would be 12.

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What are the measurements of the two angles in the figure below?

IgorC [24]

Both angles need to equal 180 degrees .

Add them together:

2x +10 + 3x-5 = 180

5X +5 = 180

Subtract 5 from each side:

5x = 175

Divide both sides by 5:

X = 175 / 5

X = 35

Now replace X with 35 in each equation:

2x +10 = 2(35) +10 = 70 +10 = 80

3x-5 = 3(35) - 5 = 105 -5 = 100

The answer is A. 80 and 100

5 0

3 years ago

At the beginning of a semester an anonymous survey was conducted on students in a statistics class. Two of the questions on the

kati45 [8]

Answer:

a. Chi-square test of independence

Step-by-step explanation:

The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.

In the given problem the Equal , more or less are the attributes.

The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0

3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

Jamal is making two paintings using canvases that are similar rectangles. The length of the smaller canvas is 3 ft and the width

Alex787 [66]

Let's start with what we know:

Smaller canvas:
Length ( $L_{1}$ ) = 3ft
Width ( $W_{1}$ ) = 5ft

Larger canvas:
Length ( $L_{2}$ ) = ?
Width ( $W_{2}$ ) = 10ft

Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

$\frac{ L_{1} }{ L_{2} } = \frac{ W_{1} }{ W_{2} }$
So let's plug it all in from above:

$\frac{ 3 }{ L_{2} } = \frac{ 5 }{ 10 }$
Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:

$(3)(10) = (5)(L_{2})$
$30 = 5L_{2}$
Now divide each side by 5 to isolate $L_{2}$

$\frac{30}{5} = \frac{ 5L_{2}}{5}$
The 5s on the right cancel out, leaving us with:

$6 = L_{2}$

So the length of the larger canvas is 6 ft

4 0

3 years ago

Read 2 more answers

Solve the equation 5x + 8 - 3x = -10 OX= -9 O x = -1 ON=1 O X = 9

Leokris [45]

Answer:

its OX= -9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers