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V125BC [204]
3 years ago
6

Nooooooooooooooooooooooo

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer: yes

Step-by-step explanation:

Simply just yes

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In a sociology class there are 1414 sociology majors and 1111 non-sociology majors. 33 students are randomly selected to present
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Answer: 0.4065

Step-by-step explanation:

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Then, the number of ways to select 3 students from 25 students :-

^{25}C_3=\dfrac{25!}{(25-3)!3!}=\dfrac{25\times24\times23\times22!}{22!3!}\\\\=2300

Number of ways to select  at least 2 of the 3 students re non-sociology majors :-

^{14}C_1\times^{11}C_2+^{14}C_0\times ^{11}C_{3}\\\\=(14)\times\dfrac{11!}{2!(11-2)!}+(1)\times\dfrac{11!}{3!(11-3)!}\\\\=(14)(11\times5)+\dfrac{11\times10\times9}{6}\\\\=770+165=935

The probability that at least 2 of the 3 students selected are non-sociology majors will be :-

\dfrac{935}{2300}=0.40652173913\approx0.4065

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