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storchak [24]
3 years ago
10

With the growth of internet service providers, a researcher decides to examine whether there is a correlation between cost of in

ternet service per month and degree of customer satisfaction (higher scores mean high satisfaction). The researcher only includes programs with comparable types of services. Calculate the Pearson's correlation coefficient for the dataset below and interpret what that means.
Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer:

The correlation is 0.373 . There is a moderate positive linear association between Dollars and Satisfaction.

Step-by-step explanation:

Given the data:

Dollars Satisfaction

70.99 32

76.01 34

67.24 27

69.33 17

67.59 23

74.06 29

76.04 25

72.63 31

68.01 26

67.98 31

Using technology, the Pearson correlation Coefficient calculator ; we can obtain the Pearson correlation Coefficient is 0.3729

Interpretating this value, a correlation Coefficient value of 0.3729 is positive, this means a positive linear relationship exists between the values. Also 0.3729 is closer to 0 than 1 ; this mean that the strength of their relationship is moderate to weak .

Hence, a correlation Coefficient value of 0.3729 means that a weak positive relationship exists between dollar and satisfaction

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An airplane descends 2.2 miles to an elevation of 8.55 miles. Find the elevation of the plane before its descent.
lutik1710 [3]

Answer:

10.75 miles was the elavation before it's decsecent.

Step-by-step explanation:

Hope this helps! :)

7 0
3 years ago
A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the
charle [14.2K]

Answer:

\dfrac{dy}{dt}=0.27-0.009y(t),$  y(0)=60kg

Step-by-step explanation:

Volume of water in the tank = 1000 L

Let y(t) denote the amount of salt in the tank at any time t.

Initially, the tank contains 60 kg of salt, therefore:

y(0)=60 kg

<u />

<u>Rate In</u>

A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.

R_{in} =(concentration of salt in inflow)(input rate of solution)

=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}

<u>Rate Out</u>

The solution is mixed and drains from the tank at the same rate.

Concentration, C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}

R_{out} =(concentration of salt in outflow)(output rate of solution)

=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}

Therefore, the differential equation for the amount of Salt in the Tank  at any time t:

\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$  y(0)=60kg

8 0
4 years ago
Which measure is equivalent to 1.2 km?
Anna11 [10]

Answer:

correct answer: 120,000 cm!

8 0
3 years ago
Read 2 more answers
Uwu this isnt a test but its practiceee
igor_vitrenko [27]

<u>Answer</u>: B, (-3/2, -1)


<u>Step-by-step explanation:</u>

When you use the midpoint formula, (x1+x2/2 , y1+y2/2) you end up taking one away from -4, and dividing it by 2 (-3/2), and when you add 2 to -4, you get -2, divided by 2, is -1.


4 0
3 years ago
What is the correct order to represent 92,232
Marina CMI [18]
Wdym, do you mean like 90,000+ 2,000+200+30+2
7 0
4 years ago
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