Carl went to the toy store with a total of $17.25. He wanted to buy

Mathematics

2 answers:

AlekseyPX2 years ago

6 0

The answer to the question is 9

Citrus2011 [14]2 years ago

6 0

Answer:

Step-by-step explanation:

Just divide 17.25 by 1.83 and you will get the answer. You'd get 9.4 but you can't have .4 of something so it is just 9.

You might be interested in

The perimeter of a rectangle is 22 inches. Find the dimensions if its length is 3 inches greater than its width.

MaRussiya [10]

Answer:

Length: 7

Width: 4

Step-by-step explanation:

We can create a system of equations for this problem, where $w$ is the width and $l$ is the length.

The perimeter of a rectangle is twice its length added to twice its width.

$2l+2w=22$

The length is 3 more than the width:

$l = w+3$

We can now substitute in $w+3$ as $l$ in the equation $2l+2w=22$ .

$2(w+3) + 2w = 22$

Distribute the first terms:

$2w+6+2w=22$

Combine like terms:

$4w+6=22$

Subtract 6 from both sides:

$4w=16$

Divide both sides by 4:

$w = 4$

Now we know that w = 4. We can now substitute this inside an equation to find $l$ .

$l = w+3\\\\l = 4+3\\\\l=7$

Hope this helped!

7 0

3 years ago

Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will

Paraphin [41]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill$