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3 years ago

What is the slope of the line passing through points (6, -1) and (1,8)?

Mathematics

1 answer:

Fynjy0 [20]3 years ago

7 0

Answer:

-1.8

Step-by-step explanation:

m= y2 - y2over x2 - x1

m= -1 - 8 over 1 - 6 = -1.8

m= -1.8

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Calculate the volume of the cylinder. Use button, not 3.14. Round answer to the tenth place.

Volgvan

Answer:

68.69 m^3

Step-by-step explanation:

Volume of cone = $\frac{1}{3}\pi r^{2}h$

= $\frac{1}{3}\pi (2.9^{2})(7.8)$

= $\frac{1}{3}\pi (65.6)\\$

= $\frac{1}{3}(206)$

$= 68.69 m^3$

7 0

3 years ago

In a recent survey, two-thirds of the 234 students in a freshman class said they watch television shows on their computer. Deter

stellarik [79]

We know that 2/3 of all students watch TV shows on their computers.
And 234 students were in that survey.
2 / 3 * 234 = 156
Answer: 156 students watch shows on their computer.

3 0

4 years ago

Read 2 more answers

A gift box is in the shape of a trapezoidal prism with base lengths of 7 inches and 5 inches and a height of 4 inches. The heigh

jek_recluse [69]

First of all there are multiple formula's to get the volume of a trapezoidal prism:

V=(1/2 * (base1 + base2) * h) * height prism

Using the numbers you gave:
base1 = 7 base2 = 5 h = 4 height prism = 8

Putting this into the equation: V=(1/2 * (7 <span>+ 5) * 4) * 8
V= (1/2 * 12 * 4) * 8
V = 24 * 8
V = 192

The volume of the gift box is 191 inches squared.</span>

6 0

4 years ago

A teenager can wash 2

leva [86]

2 * M = X
M = to minutes
x = to how many tables washes

3 0

4 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago