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forsale [732]
3 years ago
15

Is this equation even or odd? Please answer asap

Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

The equation represents an even function

Step-by-step explanation:

For the function above, the value of f(x) is fixed at 3 for positive or negative values of x.

For the absolute value function below, the value of f(x) will always be positive due to the absolute symbol.

In general, a function f(x) is said to be even if;

f(-x) = f(x) such that the function is symmetrical with respect to the y-axis.

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33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
If product of two numbers=384HCF=8,2cm=?​
lions [1.4K]

Answer:

96 and 288

Step-by-step explanation:

So, we need to find 2 numbers such that their sum is 8 and they do not have common factor (Relatively prime). Both these numbers will be divisible by 48 but there would be no other common divisor (after dividing by 48).

Such order independent pairs are (1,7) and (3,5).

Difference between them would be (7–1)*48=6*48 and (5–3)*48=2*48 respectively.

The differences are 6*48=288 and 2*48=96.

We have found difference without finding numbers.

Ans.: 96 and 288

p.s.: The number pairs (again order neutral) would be (48, 336) and (144, 240)

Difference for 48 and 336 add up to 384, their HCF is 48. These two numbers match the conditions. Their difference is 288.

Difference of 144 and 240 add up to 384, their HFC is 48 (the numbers are 48*3 and 48*5, common factor is 48 and no other common factor for 3 and 5; 48 is HCF). The difference is 96.

6 0
3 years ago
Red: y = 7x
Degger [83]

Answer:

Green

Step-by-step explanation:

3 0
3 years ago
Write the number with the same value as 28 tens
Brut [27]
The answer is 280 because you multiply by 10
4 0
4 years ago
Read 2 more answers
What I should put in these boxes.
lina2011 [118]
Instead of putting the diving put the multiply and you’re answer will be correct
6 0
3 years ago
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