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ira [324]
4 years ago
9

{2y-4}=12 what are the solutions?

Mathematics
2 answers:
Hatshy [7]4 years ago
7 0

Answer:

y=8

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Firlakuza [10]4 years ago
7 0

Answer:There are no solutions.

Step-by-step explanation:

I inputed in my calculator and went to the chart, then was no real solutions.

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A cylinder shaped drum is used as a garbage container. The drum has a height of 4 ft and a radius of 1.25 ft.
Marina86 [1]
V=hpir^2
h=4
r=1.25
v=4pi1.25^2
v=4pi1.5625
v=6.25pi
v=19.625
rounded to hundreth
v=19.63 ft³
7 0
4 years ago
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Write a quadratic function with zeros -3 and 6.<br> Answer is in standard form.
Sergeu [11.5K]
1. Write the factors
(x+3)(x-6) = 0

2. Multiply the factors to get the answer in standard form
x^2 + 3x - 6x - 18 = 0

3. Simplify
x^2 - 3x - 18 = 0
7 0
3 years ago
Please teach me how to do this question..tq​
nikitadnepr [17]

Answer:

Emilia bought 28 sweets

Step-by-step explanation:

now they have 65, but before they had 65-15+10 because earlier, zakiah had ten more sweets than now and Emilia had 15 less, so basically, if you wanna calculate number of sweets they had earlier, you have to make minus from plus and in reverse too.

65-15+10=60 and now just do that simply ratio

E:Z=7:8

E+Z=7x+8x

60=15x

4=x

7x=28=Emilia

8x=32=Zakiah

Accuracy test:

(28+15)+(32-10)=65

28 is 4•7 and 32 is 4•8

3 0
4 years ago
What is eight thirds equivilent to
STatiana [176]
Eight thirds (also known as 8/3) is equivalent to two and two thirds (numerically written: 2 2/3). Explanation: to solve this, find out god many times 3 can fit into eight. Three can fit into eight 2 times (since 3*2 is 6), which leaves you with 2 left. Since this remainder of 2 can not be divided by 3, it is put into a fraction of 2/3. Therefore, the answer is 2 2/3.
3 0
4 years ago
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Z^m-n (z^m+ z^m+n + z^n)
rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

8 0
3 years ago
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