If;
A = Adjacent
O = Opposite
H = Hypotenuse
Then,
Sin Ф = O/H
Cos Ф = A/H
Therefore,
(Sin Ф)/Cos Ф) = (O/H)/(A/H) = (O/H)*(H/A) = O/A
Now,
tan Ф = O/A ----
Therefore, it is true that
tan Ф = SinФ/CosФ
Answer: it’s the first one
Step-by-step explanation:
Sub those points for x
f(x) is the y
(x,y)
so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint
for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point
for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point
points are
(0,3)
(1,5)
(2,35)
The answer is 9
sqrt(49) = 7
4^2 = 16
16-7 = 9
The answer is f when 2,3 is put in for the x and y then 18 should come out 3×2=6
4×3=12 12+6=18
