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3 years ago

62 . 52 = 27 . 39 + t

Mathematics

1 answer:

BartSMP [9]3 years ago

5 0

Answer:

t = 35.13

Step-by-step explanation:

Simplifying

62.52 = 27.39 + t

Solving

62.52 = 27.39 + t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-1t' to each side of the equation.

62.52 + -1t = 27.39 + t + -1t

Combine like terms: t + -1t = 0

62.52 + -1t = 27.39 + 0

62.52 + -1t = 27.39

Add '-62.52' to each side of the equation.

62.52 + -62.52 + -1t = 27.39 + -62.52

Combine like terms: 62.52 + -62.52 = 0.00

0.00 + -1t = 27.39 + -62.52

-1t = 27.39 + -62.52

Combine like terms: 27.39 + -62.52 = -35.13

-1t = -35.13

Divide each side by '-1'.

t = 35.13

Simplifying

t = 35.13

hope it helps !!!!!!!!!!! :)

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3 years ago

Given the following proportion, find x<br><br> 3/7 = 6/x

Novosadov [1.4K]

Answer:

x = 14

Step-by-step explanation:

3/7 = 6/x

3(x) = 6(7)

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3 years ago

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

what is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 3/4?

Troyanec [42]

Y = mx + b
slope(m) = 3/4
(5,-4)...x = 5 and y = -4
now we sub
-4 = 3/4(5) + b
-4 = 15/4 + b
-4 - 15/4 = b
-16/4 - 15/4 = b
- 31/4 = b....or - 7 3/4 = b

so ur equation is : y = 3/4x + (-31/4) or y = 3/4x - 31/4

3 0

3 years ago

Need help again with this

nalin [4]

I think it would be B

7 0

3 years ago

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