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Lelu [443]
3 years ago
11

A number and its absolutely value are equal. If you subtract 2 from the number and its absolute value are not equal. What do you

know about the number? What is a possible number that satisfies these conditions?
Mathematics
1 answer:
Naily [24]3 years ago
5 0
n-the\ number\\\\|n|=n\ then\ n\geq0\\\\|n-2|\neq n-2\ what's\ a\ number\\\\I\ think,\ it's\ n=1\\\\because\ |1|=1\ and\ |n-2|=|-1|=1\ \ \ :correct\ \ :)\\\\3\ is\ not,\ because:\ |3|=3\ and\ |3-2|=|1|=1\to3\neq1
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What is the scale factor of this dilation? <br><br> 1/2, <br><br> 2/3, <br><br> 3/4, <br><br> 3/2
Butoxors [25]

3/4,  is right i think

6 0
3 years ago
In the 1980s land prices in Japan surged upward in a ""speculative bubble."" Land prices then fell for 11 straight years between
Aloiza [94]

Answer:

Step-by-step explanation:

Given the supply of land is perfectly inelastic, the drop in prices must have resulted from decreased demand for land. The demand for land would fall if there were less of a return on the land (i.e., rent), so we can safely assume that land rent fell in Japan between 1990 and 2001. The shifts from D3 to D2 to D1 demonstrate graphically what happened in Japan.

7 0
3 years ago
Find the slope between the two points (6,8)<br> (10,11)<br> -3/4<br> 3/4<br> 19/16<br> 4/3
Kazeer [188]

Answer:

Slope = \frac{3}{4}

Step-by-step explanation:

(x₁ , y₁) = (6 , 8)   &  (x₂ , y₂) = (10 , 11)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\

        = \frac{11-8}{10-6}\\\\=\frac{3}{4}

5 0
3 years ago
EVALAUTE: 5|7 - 9| - 2=<br><br> a. -12<br> b. 0<br> c. 1<br> d. 8
alexandr1967 [171]
It’s d!!!!!!!!!!!!!!
3 0
4 years ago
What is the least common denominator for the rational expressions 1 / x² -5 x-6} and 1/x²-12 x+36 ? Show your work.
enot [183]

The least common denominator for the rational expressions 1/x²-5x-6 and 1/x²-12 x+36 is  (x-6)(x+1)(x-6).

In the given question

=\frac{1}{x^{2} -5x-6} , \frac{1}{x^{2} -12x+36}  ...(i)

First we will factor each denominator

So,

x²-5x-6

On splitting the factors of the above expression , we get

(x+1)(x-6)   ....(ii)

x²-12x+36

On splitting the factors of the above expression , we get

(x-6)(x-6)    ...(iii)

Substituting the value of (ii) and (iii) in (i) ,we get ;

=\frac{1}{(x+1)(x-6)} , \frac{1}{(x-6)(x-6)}

As the LCM of denominator is the Least common denominator , we have

LCM of (x+1)(x-6) and (x-6)(x-6)

LCM=(x-6)(x+1)(x-6)

Hence the LCD is (x-6)(x+1)(x-6).

Therefore , the least common denominator for the rational expressions 1/x²-5x-6 and 1/x²-12 x+36 is  (x-6)(x+1)(x-6).

Learn more about Least Common Denominator here brainly.com/question/11879136

#SPJ4

7 0
1 year ago
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