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3 years ago

Fill in the table using this function rule. y=-2x +4

Mathematics

1 answer:

Anton [14]3 years ago

3 0

Answer

i think this is what you mean

Step-by-step explanation:

x y

2 0

1 2

0 4

-1 6

-2 8

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3 years ago

Solve 4 + 2 sinx= 14-8 sinx for 0° ≤ x ≤ 180

Oduvanchick [21]

<h2>Answer:</h2>

<u>x= 90°</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

$4 + 2 sin(x)= 14-8 sin(x)$

<h3>2. Subtract "4" from both sides of the equation.</h3>

$-4+4 + 2 sin(x)= 14-8 sin(x)-4\\ \\2 sin(x)= 10-8 sin(x)$

<h3>3. Add "8sin(x)" to both sides of the equation.</h3>

$2 sin(x)+8 sin(x)= 10-8 sin(x)+8 sin(x)\\ \\10 sin(x)= 10$

<h3>4. Divide both sides by 10.</h3>

$\frac{10 sin(x)}{10} = \frac{10}{10} \\ \\sin(x)=1$

<h3>5. Apply the arcsin of sin^-1 to both sides of the equation.</h3>

$arcsin(sin(x))=arcsin(1)\\ \\x=90$

<h3>6. Conclude.</h3>

<u>x= 90°</u>.

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2 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

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4 years ago