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worty [1.4K]
3 years ago
5

What is 5=-2/3x+b X=4 I’ll give Brainlylist

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

b = 23/3

Step-by-step explanation:

5 = -2/3(4) + b

5 = -8/3 + b

5 + 8/3 = b

b = 23/3

You might be interested in
Is the fraction 13/8 a rational number
Talja [164]
Yes. Any number that can be written as a fraction is defined as rational.
4 0
3 years ago
A coordinate plane from negative 8 to 8 along the x-axis and from negative 7 to 7 along the y-axis. Which steps should be used t
sdas [7]

Answer:

see the explanation

Step-by-step explanation:

we have

y-4=\frac{1}{3}(x+2)

This is the equation of a line in point slope form

where

the point is (-2,4)

the slope is m=1/3

Remember that the formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)

so

To graph the line

1. Plot the point (–2,4).

2. From that point, count left 3 units and down 1 unit and plot a second point.

3. Draw a line through the two points

3 0
3 years ago
Read 2 more answers
Where does the parentheses go in 3+6 ×9+3 to made a total of 84​
chubhunter [2.5K]

Answer:

Around the 3 + 6:-

(3 + 6) x 9 + 3

Step-by-step explanation:

(3 + 6) x 9 + 3

= 9 x 9 + 3

= 84.

4 0
3 years ago
Read 2 more answers
Translate this sentence into an equation.<br> 45 is the sum of 19 and Victor's score
Alex17521 [72]

Answer:

Victors score= v

19 + v =45

5 0
3 years ago
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
3 years ago
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