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Sunny_sXe [5.5K]
3 years ago
6

what is the answer to this At a sale, shirts were sold for $15 each. This price was 80% of their original price. What was the or

iginal price?
Mathematics
2 answers:
pogonyaev3 years ago
7 0

x \cdot \dfrac{8}{10 } = 15 \\~\\~\\x = \dfrac{5\cdot15}{4} \\~\\~\\ x= 18.75

Otrada [13]3 years ago
3 0

Answer:

18.75

Step-by-step explanation:

15/.8 ro80%= 18.75

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A tarp is used to keep the infield of a baseball field from getting wet. The infield is a square. The corners of the square tarp
Dafna11 [192]

Answer:

<h2>a. 2,025 ft</h2><h2>b. 8,100 is a perfect square. </h2>

Step-by-step & explanation:

<em>It is a perfect square because if it wasn't, it wouldn't be equally a whole number when divided by 4 or 2,025 exactly on ALL 4 sides and when finding the root of 8,100 it's a perfect 90.  As you should already know a perfect square has a given 90 degree angle.</em>

Tarp = 8,100 sq ft.

- anchored corners at the base.

- Square infield.

Well if there's 4 bases, divide 8,100 by 4.

8,100 / 4 = 2,025

One base to another base is 2,025 ft.

8 0
3 years ago
PLEASEE HELP THIS IS DUE TODAY
dangina [55]

Answer:

The first one is 360 degrees. The second one is 1080.

Step-by-step explanation:

The sum of the interior angles of a quadrilateral are always 360. If you subtract 90 from 360 to get 270. Multiply 270 by 4 to get 1080.

7 0
3 years ago
Solve the compound inequality, then correctly fill in the blanks below.<br> -3 2-5 &lt;2<br> I
lesantik [10]

Answer:

hold my picolr

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP
sweet [91]
The answer is 10 I just subtracted it so
5 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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