Answer:
Step-by-step explanation:
x-intercepts exist where y is equal to 0. Where y is equal to 0 is where the graph goes through the x-axis. Our x-intercepts are (2x-3), (x + 3), and (x-4). Again, since x-intercepts exist where y = 0, then by the Zero Product Property, 2x - 3 = 0, x - 4 = 0, and x + 3 = 0. In the first x-intercept:
2x - 3 = 0 and
2x = 3 so
x = 3/2
In the second:
x - 4 = 0 so
x = 4
In the third:
x + 3 = 0 so
x = -3
So the x-intercepts in the correct order are x = 3/2, 4, -3
Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer: x = 0
Step-by-step explanation:
1 - 3x = 3x + 1
then add 3x on both sides
1 = 6x + 1
then subtract 1 on both sides
0 = 6x
then divide by 6 on both sides
0 = x
so x = 0
It should be the 3rd one but idk for sure. if its not then its the 3rd one
Answer:

Step-by-step explanation:

I hope that uesful for u :)