Answer:
The answer is probably A
Step-by-step explanation:
Its domain is the only one of these that contain -2, which is a real number.
EMERGENCY CORRECTION: THIS IS WRONG AND I'M TOO ST*PID TO FIGURE OUT THE REAL ANSWER I'M SORRY
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
31 divided by 3 is 10.33 repeated
Answer:
2
Step-by-step explanation:
x times x is x^2
You would find the multiples 2 and 3 had in common
so may 6th, 12th, and 18th
2: 3:
4 6*
6* 9
8 12*
10 15
12* 18*
14
16
18*
