Answer:
Step-by-step explanation:
a) True. Let I integer = 2m+1 and second integer 2n+1
Difference = 2(m-n) hence even
b)False. If m and n are integers and m+n is odd then either both even or both odd
Eg: 3 and 5. 3+5 =8 is even but both are even
c) True
m is odd then m= 2n+1
l is even so l = 2p
Sum = 2(n+p)+1 hence odd
Answer:
2700 in^2
Step-by-step explanation:
30x30x3(which is how they are rounding π) = 2700 in ^2
Top row is x= 10, x^2 =100, x^3 = 1000
Bottom row is 5, 25, 125
7 places in without standard form