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hodyreva [135]
3 years ago
13

Karen spent 7/10 hour reading and 3/5 hours writing in her journal how much longer did karen spend reading than writing in her j

ournal
Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer: 1/10

Step-by-step explanation:

From the question, we are informed that Karen spent 7/10 hour reading and 3/5 hours writing in her journal.

To calculate how much longer karen spent reading than writing in her journal, we have to subtract 3/5 from 7/10. This will be:

= 7/10 - 3/5

Note that the lowest common multiple of 5 and 10 is 10.

= 7/10 - 6/10

= 1/10

Therefore, the answer is 1/10

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Complete the square and write in standard form. Show all work.What would be the conic section:CircleEllipseHyperbolaParabola
mote1985 [20]

ANSWER

This is an ellipse. The equation is:

\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1

EXPLANATION

We have to complete the square for each variable. To do so, we have to take the first two terms and compare them with the perfect binomial squared formula,

(a+b)^2=a^2+2ab+b^2

For x we have to take 16x² and -32x. Since the coefficient of x is not 1, first, we have to factor out the coefficient 16,

16x^2-32x=16(x^2-2x)

Now, the first term of the expanded binomial would be x and the second term -2x. Thus, the binomial is,

(x-1)^2=x^2-2x+1

To maintain the equation, we have to subtract 1,

16(x^2-2x+1-1)=16((x-1)^2-1)=16(x-1)^2-16

Now, we replace (16x² - 32x) from the given equation by this equivalent expression,

16(x-1)^2-16+9y^2+72y+16=0

The next step is to do the same for y. We have the terms 9y² + 72y. Again, since the coefficient of y² is not 1, we factor out the coefficient 9,

9y^2+72y=9(y^2+8y)

Following the same reasoning as before, we have that the perfect binomial squared is,

(y+4)^2=y^2+8y+16

Remember to subtract the independent term to maintain the equation,

9(y^2+8y)=9(y^2+8y+16-16)=9((y+4)^2-16)=9(y+4)^2-144

And now, as we did for x, replace the two terms (9y² + 72y) with this equivalent expression in the equation,

16(x-1)^2-16+9(y+4)^2-144+16=0

Add like terms,

\begin{gathered} 16(x-1)^2+9(y+4)^2+(-16-144+16)=0 \\ 16(x-1)^2+9(y+4)^2-144=0 \end{gathered}

Add 144 to both sides,

\begin{gathered} 16(x-1)^2+9(y+4)^2-144+144=0+144 \\ 16(x-1)^2+9(y+4)^2=144 \end{gathered}

As we can see, this is the equation of an ellipse. Its standard form is,

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

So the next step is to divide both sides by 144 and also write the coefficients as fractions in the denominator,

\begin{gathered} \frac{16(x-1)^2}{144}+\frac{9(y+4)^2}{144}=\frac{144}{144} \\  \\ \frac{(x-1)^2}{\frac{144}{16}}+\frac{(y+4)^2}{\frac{144}{9}}=1 \end{gathered}

Finally, we have to write the denominators as perfect squares, so we identify the values of a and b. 144 is 12², 16 is 4² and 9 is 3²,

\frac{(x-1)^2}{(\frac{12}{4})^2}+\frac{(y+4)^2}{(\frac{12}{3})^2}=1

Note that we can simplify a and b,

\frac{12}{4}=3\text{ and }\frac{12}{3}=4

Hence, the equation of the ellipse is,

\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1

3 0
1 year ago
SOMEONE PLEASE HELP ME WITH THESE 3 MATH QUESTIONS!!!!!
Len [333]

Look at the pictures (examples)

m∠1 = m∠6 → answer: none

m∠2 = m∠3 → answer: none

m∠2 = m∠C → answer: none



7 0
4 years ago
What is the inverse of the function f(x)= 6x-5/x+9
Goshia [24]

Answer:

Inverse of -5-9x/x-6

Step-by-step explanation:

Steps:

1: Interchange the variables x and y.      

x=6y-5/y+9

2: Solve x = 6y-5/y+9 for y

3: Multiply both sides by y+9

4: Simplify and Expand

5: Subtract 9x from both sides.

6: Simplify and Subtract y from both sides then Simplify again

7: Divide both sides by x-6

Answer: Inverse of -5-9x/x-6

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Read 2 more answers
What is the value of the expression below when w = 5?<br> 2w2 – 2w + 3
bagirrra123 [75]

Answer:

I got you

Step-by-step explanation:

2 time 5 times 2 is 20. This minus 2 times 5 is 10 plus 3 is 13.

5 0
3 years ago
Given ZW=20. Answer the questions please. ​
djyliett [7]

a) Corresponding angles of similar figures are congruent, so \angle B \cong \boxed{\angle Z}

b) Scale factor = (image)/(preimage). Since we are looking for ABCD to WZYX, this means that WZYX is the image and ABCD is the preimage. Thus, the scale factor is \frac{25}{10}=\boxed{5/2}

c) Since the scale factor is 5/2,

\frac{20}{t}=\frac{5}[2}\\\\40=5t\\ \\ t=\boxed{8}

8 0
2 years ago
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