Answer:
y−3=2(x+3)
y=2x+9
that's the answer hope this helps u
The information given about the proof does that Daniel made an error on line 2.
<h3>How to illustrate the information?</h3>
Given:
1. AB = 3x +2; BC = 4x + 8; AC = 38
2. AB + BC = AC incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38 correct
4. 7x + 10 = 38 correct
5. 7x = 28 correct
6. x = 4
Daniel made an error on line 2.
Here is the complete question:
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5
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Answer:
The answer is 2427.5
Step-by-step explanation:
The fraction consists of two numbers and a fraction bar: 4,855/200
The number above the bar is called numerator: 4,855
The number below the bar is called denominator: 200
The fraction bar means that the two numbers are dividing themselves.
To get fraction's value divide the numerator by the denominator:
Value = 4,855 ÷ 200
To calculate the greatest common factor, GCF:
1. Build the prime factorizations of the numerator and denominator.
2. Multiply all the common prime factors, by the lowest exponents.
Factor both the numerator and denominator, break them down to prime factors:
Prime Factorization of a number: finding the prime numbers that multiply together to make that number.
4,855 = 5 × 971;
4,855 is a composite number;
In exponential notation:
200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;
200 is a composite number;
Answer:
879cm
Step-by-step explanation:
Radius is 35cm.
Diameter is 70cm.
Pie/Pi is 3.14 and so on.
Perimeter of circle:70×3.14=219.8
219.8×4=879.2
Round Off:879.2cm
1. A in some part is correct, but the triangles are indeed correct, and the argument is for HL, so the answer is C
2. Are congruent by SSS (both shares a side).
