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2 answers:
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9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
d=1
Step-by-step explanation:
Lets factor the denominator d^2 -2d-8
d^2 - 2d - 8 = (d-4)(d+2)
Now make the denominators same
LCD: (d-4)(d+2)
Denominators are same on both sides
So equate the numerators
-3d +3(d+2) = -2(d-4)
-3d +3d +6 = -2d +8
6 = -2d + 8
subtract 8 on both sides
-2 = -2d
So d=1
The awnser is 367.38 to the 3rd power only if its volume but if its surface area then it would be to the 3rd power. do u get it?
