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natali 33 [55]
2 years ago
11

Can someone help with this question

Mathematics
1 answer:
nevsk [136]2 years ago
5 0

Answer:

It should I only looked at the first few columns and the matched up

Step-by-step explanation:

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1 1/2x4 1/4 solve problem in simplest form
olganol [36]

Answer:

6 3/8

Step-by-step explanation:

1.5x4.25=6.375=51/8= 6 3/8

8 0
2 years ago
PHOTO ATTACHED PLEASEEEE HELPPPP!!!!!!!!!!
Thepotemich [5.8K]

Answer:

15x^2-3x-1

Step-by-step explanation:

All we have to do is collect like terms and calculate! Hope this helps!

6 0
2 years ago
Anwser true or false
m_a_m_a [10]
False because doing the math doesn’t match
6 0
2 years ago
Read 2 more answers
Which of the following is the reciprocal of x2 – 2x – 8?
Ann [662]
Hi again

x² - 2x - 8
Factor
= (x + 2)(x -4)
Answer : A is the correct option.


If you wanna check if A is the right answer, I will solve it for you and it will you give you the exact answer which will be x² - 2x - 8
(x+2)(x-4)
Distribute
(x)(x) + (x)(-4)+(2)(x)+(2)(-4)
= x² - 4x + 2x - 8
= x² - 2x - 8
Here it is, we find the exam answer.

Thus, (x+2)(x-4) is the reciprocal of x² -2x - 8


I hope that's help !
6 0
3 years ago
You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that \sigma = 12000

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

M = z\frac{\sigma}{\sqrt{n}}

1000 = 1.96\frac{12000}{\sqrt{n}}

1000\sqrt{n} = 1.96*12

Dividing both sides by 1000:

\sqrt{n} = 1.96*12

(\sqrt{n})^2 = (1.96*12)^2

n = 553.2

Rounding up:

A sample size of 554 is needed.

5 0
2 years ago
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