1- a
2- d
3- abd
4- d
5- a
sorry if wrong
Answer:
first of all square mean two number or double so if we multiple 15×15=225 and if we multiply 16×16=256 mean the number 240 lies between them what about number 15.5 lets try now 15.5×15.5=240.25 if you want to make sure so just take a square root of this number
so 240 is product of (15.5)² note number after point is negligible
Answer:
mu = x√P(x) - £
£ = x√P(x) - xP(x)
Step-by-step explanation:
We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"
Equation 1
mu = £[xP(x)]
Equation 2
£^2 = x^2 P(x) - (mu)^2
Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.
Hence sigma is equal to
[x√P(x) - mu] ...(3)
Since mu = xP(x), we substitute this into equation (3) to get
Sigma = x√P(x) - xP(x)
mu = x√P(x) - £
Answer: the probability of a student being overdrawn by more than $18.75 is 0.674
Step-by-step explanation:
Since the bank overdrafts of ASU student accounts are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = bank overdraft of Asu students.
µ = mean
σ = standard deviation
From the information given,
µ = $21.22
σ = $5.49
We want to find the probability of a student being overdrawn by more than $18.75. It is expressed as
P(x > 18.75) = 1 - P(x ≤ 18.75)
For x = 18.75,
z = (18.75 - 21.22)/5.49 = - 0.45
Looking at the normal distribution table, the probability corresponding to the z score is 0.326
Therefore,
P(x > 18.75) = 1 - 0.326 = 0.674
Answer:
x = {2, -10}
Step-by-step explanation:
In this equation, you can solve for x like this:
To get 2:
3x + 12 = 18 (Subtract 12 from both sides)
3x = 6 (Divide both sides by 3)
x = 2
To get -10:
3x + 12 = -18
3x = -30
x = -10
