3 years ago

Find the Area of the Polygons:

Mathematics

2 answers:

elena-s [515]3 years ago

7 0

Answer:

480

Step-by-step explanation:

Leto [7]3 years ago

3 0

Answer:

ABCE) 48

CDE) 36

ABCDE ) 48+36=84

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Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

3 years ago

25h + 40 = −15h − 80

elena-s [515]

Answer:

Step-by-step explanation:

25h + 40 = −15h − 80

25h + 15h = -80 - 40

40h = - 120

h = -120/4

h= -3

4 0