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zubka84 [21]
3 years ago
6

9) What is the result of adding 3 to -3?​

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
5 0

Answer:

3 to -3? = 0

Step-by-step explanation:

Hope this helped you!

NISA [10]3 years ago
3 0

Answer:

0

Step-by-step explanation:

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Lol help me for a brainliest
Dmitrij [34]

Answer:  \bold{b)\quad \dfrac{17}{36}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{1}{6}\bigg(2\dfrac{1}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{7}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{28}{12}-\dfrac{9}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{19}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{15}{72}\\\\\\=\dfrac{34}{72}\\\\\\=\large\boxed{\dfrac{17}{36}}

3 0
3 years ago
Read 2 more answers
How much is x? Round it to the nearest tenth.
valkas [14]

Answer:

The answer is 7.3

Step-by-step explanation:

8 0
4 years ago
(x) = 3x + 5, what is the value of f (5)?
borishaifa [10]

Answer:

the answer is 20 .put the 5 in place of x                                                                          

and u always remember that f(5) =f(x)

Step-by-step explanation:

4 0
3 years ago
Suppose a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.00
Bingel [31]

Answer:

We conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

Step-by-step explanation:

We are given that a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.005 inch.

Assume that the population is normally distributed: 1.678, 1.681, 1.676, 1.684, 1.676, 1.679, 1.681, 1.681, 1.677, 1.676, 1.681, 1.683.

Let \sigma = <u><em>population standard deviation of the diameter of a golf ball.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.005 inch     {means that the standard deviation of the diameter of a golf ball is more than or equal to 0.005 inch}

Alternate Hypothesis, H_0 : \sigma < 0.005 inch     {means that the standard deviation of the diameter of a golf ball is less than 0.005 inch}

The test statistics that would be used here <u>One-sample Chi-square test statistics</u>;

                            T.S. =  \frac{(n-1)s^{2} }{{\sigma^{2} }}  ~ \chi^{2} __n_-_1

where, s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.00281 inch

           n = sample size = 12

So, <u><em>the test statistics</em></u>  =  \frac{(12-1)\times 0.00281^{2} }{{0.005^{2} }}  ~ \chi^{2} __1_1

                                     =  3.47

The value of chi-square test statistics is 3.47.

Also, the P-value of test statistics is given by the following formula;

                P-value = P( \chi^{2} __1_1 < 3.47) = 0.0182

Since, the P-value of the test statistics is less than the level of significance as 0.0182 < 0.05, so we reject our null hypothesis.

<u>Now, at 0.05 significance level the chi-square table gives critical value of 4.575 at 11 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of chi-square as 3.47 < 4.575, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

7 0
4 years ago
Find all values of theta in the interval [0° 360°) that have the given function value.
SOVA2 [1]

Answer:

The answer to your question is: 45° and 225°

Step-by-step explanation:

Getting tan⁻¹ 1 = 45°

Then, the angle we are looking for is 45°, let's check the for quadrangles.

First quadrangle = tan 45 = 1

Second quadrangle = 180° - 45° = 135°      tan 135 = -1

Third quadrangle = 180 + 45 = 225°           tan 225 = 1

Forth quadrangle = 360 - 45 = 315°            tan 315° = -1

8 0
3 years ago
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