A rectangular prism. The rectangular base has a length of 5 centimeters and width of 4 centimeters. What are the dimensions of t
he cross section formed by a plane intersecting this rectangular prism parallel to its base?
1 answer:
Answer:
dimension is 5cm * 4 cm
Step-by-step explanation:
As the plane is parallel to the base, the ratio between plane's length and width is equal to the ratio of that of the base. -> similar shape.
Moreover, it also divided the rectangular prism into 2 smaller rectangular prism. hence the plane is identical to the base. Hence, same dimension.
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Answer:
True
Step-by-step explanation:
Even though we cannot see the parallelogram, we can assume the dimensions of the original parallelogram is height= 3 and base= 6.
If we double the dimensions, we get:
height=6 band base=12.
The area of the original parallelogram is 18 square units.
The area of the enlarged parallelogram is 6×12= 72 square units.
Now,
Hence, the area of the larger parallelogram is 4 times more than the original.
Answer:
A) {x < −2
{y ≤ −x − 2
Step-by-step explanation:
The first step is to treat these inequalities as Slope-Intercept equations, then graph them according to what you know about the <em>rate</em><em> </em><em>of </em><em>changes</em><em> </em>[<em>slopes</em>] of the lines. Then insert the inequality symbols later and figure out which line they get, based on their symbols:
Dashed Line → >, <
Solid Line → ≥, ≤
is the vertical line with a <em>less</em><em> </em><em>than</em><em> </em>sign, so it gets the <em>dashed</em><em> </em><em>line</em>,<em> </em>whereas the other line has a <em>less</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal to</em><em> </em>sign, so this line gets the solid line.
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