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iragen [17]
3 years ago
11

A rectangular prism. The rectangular base has a length of 5 centimeters and width of 4 centimeters. What are the dimensions of t

he cross section formed by a plane intersecting this rectangular prism parallel to its base?

Mathematics
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

dimension is 5cm * 4 cm

Step-by-step explanation:

As the plane is parallel to the base, the ratio between plane's length and width is equal to the ratio of that of the base. -> similar shape.

Moreover, it also divided the rectangular prism into 2 smaller rectangular prism. hence the plane is identical to the base. Hence, same dimension.

see photo

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\large\displaystyle\text{$\begin{gathered}\sf \frac{4^{2} x^{2} }{y^{2} }  \end{gathered}$}

Calculates 4 to the power of 2 and gets 16.

\boxed{\large\displaystyle\text{$\begin{gathered}\sf \frac{16x^{2} }{y^{2} }  \end{gathered}$} }

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Convert 5 square root of a into exponential form?
stich3 [128]

Answer:

The answer is:  " 5a^\frac{1}{2} "  .

_____________________________________________

Step-by-step explanation:

______________________________________________

We are asked to convert "5 square root of a"  ;  into "exponential form".

Note that "5 square root of a" ;

             or;  " 5 root a " ;

means:    " 5 times the {square root of the variable, "a" };

      or :    " 5 multiplied by the {square root of the variable, "a" }.

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This can be written as:   " 5\sqrt{a} " .

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<u>Note the following property of exponents</u>:

\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n .

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So;  to write:  " √a "  ;  <u> </u><em><u>as an exponent</u></em><u> </u> :

______________________________________________

<u>Note</u>:  

" \sqrt{a}  = \sqrt[2]{a} =   \sqrt[2]{a^1} = (\sqrt[2]{a})^1 =  a^\frac{1}{2} " .

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<u>So</u>:

" \sqrt{a}  =  a^\frac{1}{2} "  ;

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<u>And</u>:

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" 5\sqrt{a}  =  5a^\frac{1}{2} " .

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   →   The answer is:  " 5a^\frac{1}{2} " .

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Hope this helps!

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