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katovenus [111]
3 years ago
5

Show work, please someone help me, i'm confused still on this concept.

Mathematics
1 answer:
BigorU [14]3 years ago
3 0
Answer: choice C) -15x^4y

-----------------------------------------

Explanation:

The coefficients are -3 and 5. They are the numbers to the left of the variable terms
Multiply the coefficients to get -3*5 = -15. So -15 is the coefficient in the answer

Multiply the x terms to get x^3 times x = x^(3+1) = x^4. Notice the exponents are being added

Do the same for the y terms as well: y^2 times y^(-1) = y^(2+(-1)) = y^(2-1) = y^1 = y

So we have a final coefficient of -15, the x terms simplify to x^4 and the y terms simplify to just y

Put this all together and we end up with -15x^4y which is what choice C is showing

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nasty-shy [4]

Answer: The answer is (D) f(x)=2(\dfrac{2}{3})^x.

Step-by-step explanation:  We are to select the correct function which represents exponential decay.

We know that an exponential decay is represented by the function with base less than 1.

For example, if we consider the following exponential function:

f(x)=b^x,

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Among the given functions, f(x)=2(\dfrac{2}{3})^x represents exponential decay, because the base is 0.66, which is less than 1.

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The graph of this resultant function is attached, which clearly represents exponential decay.

3 0
3 years ago
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mr_godi [17]

The minimum surface area that such a box can have is 380 square

<h3>How to determine the minimum surface area such a box can have?</h3>

Represent the base length with x and the bwith h.

So, the volume is

V = x^2h

This gives

x^2h = 500

Make h the subject

h = 500/x^2

The surface area is

S = 2(x^2 + 2xh)

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S = 2x^2 + 4xh

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S = 2x^2 + 4x * 500/x^2

Evaluate

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Differentiate

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Multiply through by x^2

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This gives

4x^3= 2000

Divide by 4

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Take the cube root

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Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

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S = 380

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Read more about surface area at

brainly.com/question/76387

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2 years ago
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Answer:

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Subtract xh/6 from both sides of the equation.

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Answer:

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Answer:

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