All categories

2 years ago

6=5x^2 - 13x factor

Mathematics

1 answer:

Serhud [2]2 years ago

6 0

Answer:

(5x-3)(x-2)(x+2)=0

Step-by-step explanation:

5x2-13x=6

5x2-13x-6=0

(5x2-10x)(-3x-6)=0

5x(x-2)-3(x+2)=0

(5x-3)(x-2)(x+2)=0

You might be interested in

If you reflect triangle MOV across the x-axis, what is the coordinate of O in the image?

Zina [86]

Hi,

The answer you are looking for is 2. (-4,2)

Have a great day & remember to mark brainliest if I helped :)

4 0

3 years ago

Read 2 more answers

An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away

daser333 [38]

The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

$\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85$

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0

3 years ago

Read 2 more answers

3 = -2x + 1 what is the value of x

DerKrebs [107]

Subtract 1 from both sides

3 - 1 = -2x

Simplify 3 -1 to 2

2 = -2x

Divide both sides by -2

-1 = x

Switch sides

4 0

3 years ago

Read 2 more answers

Twenty seven pears are packed in bags of three. Five bags of pears are sold. How many pears are left

aliya0001 [1]

Answer:

$Pears\ Left = 12$

Step-by-step explanation:

Given

$Pears = 27$

$Bags\ Sold = 5$

Required

Determine the number of bags sold

First, we need to determine the number of bags for 27 pears;

Since they are packed in 3s

$Bags = 27/3$

$Bags = 9$

Hence:

9 bags were used for 27 pears;

After 5 bags were sold, we have:

$Bags\ Left = 9 - 5$

$Bags\ Left = 4$

Recall that the pears are packed in 3s

So:

$Pears\ Left = 4 * 3$

$Pears\ Left = 12$

4 0

3 years ago

Determine g(x + a) – g(x) for the following function.<br> g(x) = 5x2 + 2x

dusya [7]

Answer:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

Step-by-step explanation:

We are given the function:

$g(x) = 5x^2 + 2x$

And we want to determine:

$\displaystyle g(x+a) - g(x)$

Substitute:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}$

And simplify:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}$

In conclusion:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

3 0

2 years ago

6=5x^2 - 13x factor ​

6=5x^2 - 13x factor