Answer:
line graph for sure ig..........
 
        
                    
             
        
        
        
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor. 
=> <u>73</u> - <u>17  </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u>       8      6     
  8 x 6       6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
      48       48 
=> <u>302 </u> or  <u>151</u>
       48          24
=> 6 <u>7</u>
       24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>
        
             
        
        
        
Answer:  hrs
 hrs
<u>Step-by-step explanation:</u>
1st painter:   
 
2nd painter: 
1st + 2nd = Together 
 +
 +  =
 = 
 +
 +  =
 = 
4x + x = 8
5x = 8
  x = 
     = 
 
        
             
        
        
        
D and H are corresponding 
G and C are corresponding 
E and A are corresponding 
B and F are corresponding
        
                    
             
        
        
        
E=Z*sqrt (p(1-p)/N), where E= error margin, p=proportion, N=sample size
Katrina's margin error at 85% confidence interval: E=1.96*sqrt (p(1-p)/100) = 0.196 sqrt (1(1-p))
Mathew's margin error at 99% confidence interval: E= 2.58*sqrt (p(1-p)/400) = 0.129 sqrt (p(1-p))
Since both obtained same estimate of proportion (that is, value of p), it can be seen that Mathew's estimate will have a small error (That is, 0.129 is smaller than 0.196). This can be attributed to larger sample size although a wider confidence (99%) interval was considered.