Question

find the volume of metal required to make a closed box of thickness 1 cm with external measurements 12 cm × 7 cm × 10​

Answer 1

Answer:

The volume of the metal is:

$V_{t}=548\: cm^{3}$

Step-by-step explanation:

First, let's find the volume of the front face of the square:

$V_{1}=12*7*1=84\: cm^{3}$

The back face is the same, so we have:  

$V_{2}=84\: cm^{3}$

The volume of the side faces will be:

$V_{3}=7*10*1=70\: cm^{3}$

$V_{4}=70\: cm^{3}$

And finally, the volume of the top and bottom side faces of the box will be:

$V_{5}=12*10*1=120\: cm^{3}$

$V_{6}=120\: cm^{3}$

The total volume of the metal will be:

$V_{t}=V_{1}+V_{2}+V_{3}+V_{4}+V_{5}+V_{6}$

$V_{t}=2(84)+2(70)+2(120)$

$V_{t}=548\: cm^{3}$

I hope it helps you!