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telo118 [61]
3 years ago
9

Helpppppp MEEEEE PLSSSS

Mathematics
2 answers:
saw5 [17]3 years ago
7 0
18.84 all you do is the v times 3.14 and that’s what you get
fiasKO [112]3 years ago
6 0
3,14•3^2= 28,26
28,26•5=141,3 m^2
You might be interested in
The radius of a circle is 16 cm. Find its area in terms of pi
anzhelika [568]
Area is 804.25 if the radius is 16cm
8 0
3 years ago
Jared measured a house and its lot and made a scale drawing. The scale of the drawing was 5 millimeters : 3 meters. The actual l
alukav5142 [94]

Answer:

115mm

Step-by-step explanation:

5/x = 3/69

5/x = 1/23

5*23 = x

115 = x

4 0
3 years ago
Find the area of the figure shown below. Use 3.14 for π and round your answer to the nearest hundredth.
topjm [15]

Answer:

ans: 111.54

Step-by-step explanation:

u can simple do by multiple

5 0
3 years ago
Read 2 more answers
The table shows a cricket club's income in 2016 from a fete, a quiz and membership fees.
kirill [66]

Answer: 5:2:10

Income from fete = £250

13 x 5 + 35 = 100

25 x 20 = 500

250:100:500

Then simplify ratio -

25:10:50

5:2:10

8 0
3 years ago
Help please :) about to post more too
yKpoI14uk [10]

Answer:

Lets say test tubes = t, and beakers = b

1 pack of (t) is $4 less than 1 pack of (b)

Since i have no prior information we are going to use variables for this equation:

1t (1 pack of test tubes) is $4 less than 1b (1 set of beakers)

so to quantify the equation, we have 8t and 12b.

if b is a number that IS quantifiable such as $5 we can easily figure out this answer.

Lets use and example that 1 set of beakers is $8, if we multiply $8 by 12 (the number of sets of beakers), we get: 96

Using the same example, if 1t is $4 less than 1b than 1t = $4. So, if we multiply $4 by 8 (the amount of packs of test tubes), we get: 32

If you take both of those numbers: 96, and 32 and you divide them you get 3. so that means that 1t = 3b

Answer = 1t = 3b

This may not be correct due to the little information that i got however i hope that, that works out for you :)

5 0
3 years ago
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