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2 years ago

The perimeter of a regular hexagon is 6x + 30. What is the length of each side of the hexagon?

Mathematics

1 answer:

Fofino [41]2 years ago

4 0

Answer:

x + 5

Step-by-step explanation:

This is actually rather simple to figure out. Simply divide 6x + 30 by 6. That should get x + 5 for the length of one side.

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What’s the slope, y-intercept, and equation of this line??

egoroff_w [7]

Answer:

Slope: 0.03

Y-intercept: 750

Equation of a line: y = 0.03x + 750

Step-by-step explanation:

See attached photo

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2 years ago

What is the exact value of BC? A. 3.16 B. 5\|2 C. 7.07 D. 25

Natalija [7]

Answer:

$C. \: \: 7.07$

Step-by-step explanation:

Coordinates of B are

$(5,5)$

Coordinates of C are

$(4, - 2)$

Distance between two points

$\sqrt{({x_2 - x _1 {)}^{2} + (y_2 - y_1 {)}^{2} }}$

Distance of BC

$\sqrt{(4 - 5) {}^{2} + ( - 2 - 5 {)}^{2} }$

$\sqrt{ { (- 1}^{2}) + ({ - 7}^{2}) }$

$\sqrt{1 +49 }$

$\sqrt{50}$

$7.07$

3 0

2 years ago

What are the acceptable diameters for the golf balls? 42.675 mm 42.6668 mm 42.664 mm 42.673 mm 72.676 mm

cluponka [151]

Answer: 42.6668mm and 42.673mm

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Using a deck of 52 playing cards, what are the odds in favor of drawing a Jack or 10?

andrey2020 [161]

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3 0

2 years ago

If x^3 + 1/x^3 = 110 then find x + 1/x

Svetlanka [38]

$Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)$

therefore

$x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}$

3 0

3 years ago