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andrew-mc [135]
3 years ago
15

Words can you make using the letters: GEOMETRY

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

TRY

MET

GET

YET

METRO

MORE

This is all i got :)

Step-by-step explanation:

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Find the slope that is PARALLEL and PERPENDICULAR to the equation of the line y = -1/2x+6.
kifflom [539]

Answer:

parallel: -1/2

perpendicular: 2

Step-by-step explanation:

lines that are parallel have the same slope because they never intersect

lines that perpendicular, have the opposite reciprocal slope.

y = mx + b

where m is the slope

y = -1/2x + 6

-1/2 is the slope.

the slope in the equation given: -1/2

the slope parallel to the line given : -1/2

the slope perpendicular : opposite reciprocal, so the opposite of -1/2 is 1/2 and the reciprocal of 1/2 is 2.

3 0
2 years ago
What is the domain of this
Kaylis [27]

Answer:

\boxed{\sf B. \ All \ real \ numbers}

Step-by-step explanation:

The domain is all possible values for x.

f(x)=(\frac{1}{4} )^x

There are no restrictions on x.

The domain is all real numbers.

3 0
3 years ago
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Which is the correct first step for solving this equation? 2x-7=5?
scZoUnD [109]

Answer:

to get x by itself so divide 5 by 2 and then add 7 to the other side

Step-by-step explanation:

2x-7=5

x-7=2.5

x=2.5+7

x=9.5

4 0
3 years ago
What is the volume if <br> the base is 48 square inches and height is 8 inches
nikitadnepr [17]

Answer:

Assuming you mean a rectangular prism, cube, or triangular prism,the volume would be 384.

Step-by-step explanation:

Well volume for those two shapes could be b*h

SO base times height is always gonna give you volume for most shapes

7 0
3 years ago
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For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
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