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3 years ago

Find the slope of a line parallel to y = 1/2x+3

Mathematics

1 answer:

VashaNatasha [74]3 years ago

5 0

Y=mx+b
m=slope

paralell lines have the same slope

y=1/2x+3
m=slope=1/2

the slope of the paralelll line is 1/2

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Mary's four friends have 1/3 of a pound of jelly bellies. They want to put them all together, how much candy do they have ?

Ne4ueva [31]

1 1/3 pounds of jelly babies.

7 0

3 years ago

Brownies are now on sale. Each brownie costs $0.20 less than the original price. Right now, if you buy 8 of them it will cost $1

Airida [17]

Answer: The original price of brownie was $2.1 each.

Step-by-step explanation:

since we have given that

Let the original price will be x

Number of brownie purchased = 8

According to question , each brownie costs $0.20 less than the original price.

So, it becomes

$8\times (x-0.20)=\$15.20\\\\8x-1.6=15.20\\\\8x=15.20+1.60\\\\8x=16.8\\\\x=\frac{16.8}{8}\\\\x=\$2.1$

Hence, the original price of brownie was $2.1 each.

5 0

3 years ago

What is the missing number in the series?<br><br> 1, 16, 81, __, 625, 1296

Alinara [238K]

Answer:

256

Step-by-step explanation:

We are given the series

1, 16, 81, __, 625, 1296

The missing number in the sequence is the fourth term

From the above sequence, we know that

1, 4², 9² , __, 25² , 36²

Difference between first term = 4 - 1 = 3

9 - 4 = 5

x - 9 = 7

x = 9 + 7 = 16

Hence, the fourth term = 16²

= 256

6 0

2 years ago

Help please

erastovalidia [21]

A = a+b/ 2 h the / is a fraction btw.

6 0

2 years ago

Read 2 more answers

A spherical balloon is inflated so that its volume is increasing at the rate of 3 ft3/min. How fast is the diameter of the ballo

beks73 [17]

When an spherical balloon volume is increasing at the rate of $3ft^3/min$ then the diameter of the balloon is increasing $\frac{3}{2\pi }ft /min$

How can we find the rate of change of balloon's diameter ?

The volume of a spherical balloon is $v=\frac{4}{3} \pi r^3$

In form of diameter we can write as

$v=\frac{4}{3} \pi (\frac{D}{2} )^3\\=\frac{1}{6} \pi D^3$

Now we will differentiate both sides wrt to $t$ we get

$\frac{dv}{dt} =\frac{1}{6} \pi 3D^2 \frac{dD}{dt} \\\frac{dD}{dt} =\frac{2}{\pi D^2} \frac{dv}{dt} \\\\when r=1\\D=2ft$

Given in the question $\frac{dv}{dt} =3ft^3/min$

thus when we substitute the values we get

$\frac{dD}{dt} =\frac{2}{\pi *2^2} (3)\\\frac{dD}{dt}=\frac{3}{2\pi } ft/min$

Learn more about the differentiation here:

brainly.com/question/28046488

#SPJ4

3 0

2 years ago