This could be a mutualism rather than a commensal relationship because when<span> "cleaner fish" consume parasites and mucus from the skin of larger fish, they don't only receive food from the relationship, eliminating parasite and such from the large fish, but also they gain protection from predators, thus making the relationship a good example of mutualism, because both parts of the relationship gain something from the relationship itself. </span>
PP- purple homozygote
pp- white homozygote
Pp- purple hetrozygote
If these flowers cross, we obtain heterozygote offsprings with a genotype: Pp (100% of them will be like this)
Now, if those offsprings cross with each other: Pp x Pp
results:
1/4 would be purple homozygote -> PP
1/4 would be white -> pp
2/4 would be purple heterozygotes -> Pp
Genotipic ratio: 3:1 (3 are purple; 1 is white)
it only need one to fertilize a egg in a flower
The answer is either a or c
Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
