Let x be the number of minutes Peg and Larry used their phones. So their costs can be written as:
Cost of Peg's Phone usage = 25 + 0.25x
Cost of Larry's Phone usage = 35 + 0.20x
We are to find when the Peg's phone will be more than Larry's phone. We can set up the inequality as:
25 + 0.25x > 35 + 0.20x
Re-arranging the inequality
0.25x - 0.20x > 35 - 25
0.05x > 10
x > 10/0.05
x > 200
Thus, Pag's phone will cost more if the number of minutes of phone usage is more than 200
Answer:
12,600 after 3 years with no withdrawals.
Ax + z = aw - y....subtract aw from both sides
ax - aw + z = -y....subtract z from both sides
ax - aw = -y - z....factor out a on the left side
a(x - w) = -y - z...divide both sides by (x-w)
a = (-y - z) / (x - w)
Answer:
$1.12
Step-by-step explanation:
12÷3=4
1 box of markers is $2.50, Multiply $2.50 by 3 and you get $7.50. 12- $7.50= $4.50. $4.50÷ 2= $2.25. $2.25÷2= $1.12
Not 100% but i'm pretty sure this is the answer. Hope this helps. ( if i'm wrong sorry its 2:30 am)
There is about 87658.1. there are 8765.81 in one year so multiply by ten to get 87658.1.
