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poizon [28]
2 years ago
15

HELLO CAN SOMEONE HELP ME IM FAILING MATH NO FAKE ANSWERS PLS TY :)

Mathematics
1 answer:
mixer [17]2 years ago
7 0

Answer:

Area of rectangle = 10 units²

Area of triangle = 10 units²

Area of figure = 20 units²

Step-by-step explanation:

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13 11/18 −7 17/18= ?
nata0808 [166]

Answer:

3 12/18 or 3 2/3

Step-by-step explanation:

you subtract them but since 11 is smaller than 17 you add 18 to it which then you subtract that by 17

8 0
3 years ago
13....................
Mashcka [7]

13.

(a)

y=-5x^2+21x-3

for x = 2:

y=-5(2)^2+21(2)-3=-20+42-3=19

for x = 5

y=-5(5)^2+21(5)-3=-125+105-3=-23

(b)

The graph is:

(c)

Using the graph:

\begin{gathered} x=1.8,y=18.6 \\ x=0.548,y=7 \\ x=3.65,y=7 \end{gathered}\begin{gathered} x=1.8 \\ y=-5(1.8)^2+21(1.8)-3=-16.2+37.8-3=18.6 \end{gathered}\begin{gathered} y=7 \\ -5x^2+21x-3=7 \\ -5x^2+21x-10=0 \end{gathered}

Using the quadratic formula:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}

6 0
11 months ago
Hello there ^ _ ^ <br><br> Can you help me please ? Please explain how you find the answer. Thanks!
ziro4ka [17]
It's C because for the perpendicular line, you need to construct cross points to draw it through.

- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.
8 0
3 years ago
-4 2/3 + 2 1/2 , I need help asp for this question help someone
snow_lady [41]

Answer:

The solution is in the attached file

7 0
2 years ago
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
2 years ago
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