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3 years ago

Understanding Transversals

Mathematics

1 answer:

Nat2105 [25]3 years ago

4 0

Answer:

Step-by-step explanation:

7 and 8 are the angles so we need to find the decimal in the problem

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Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

the ratio of 7th graders to 8th grader at a school dance is 3 to 2. there are 54 7th graders at a dance. how many 8th graders ar

Georgia [21]

I just want u to know that u are loved

6 0

3 years ago

The answer is C, but I don't understand why- can anyone tell me?

finlep [7]

Answer:

It's C because we are adding a number on the x but here we skip 5 so it's 6, and on y we add 4 up but since we skipped 5 we add 8 and we get 24. 6, 24. You may say "but SpiritBear, 17 plus eight is 25" and that is true, but if you notice the lowest dot actually starts on 5, not 4 making C right.

Hope this helped and wasn't too confusing

7 0

2 years ago

What is the quotient of 6/7 divided by 3/14

bija089 [108]

Answer:

6/7 ÷ 3/14

= 6/7 × 14/3

= 2/7 × 14 (we cancelled 3 with 6)

= 2×2 (we cancelled 7 with 14)

= 4

hope it helps

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is 5+x^2=2x^2+13?

pshichka [43]

Take the root of both sides, and solve.

x = 2i sqrt 2, -2i sqrt 2.

4 0

3 years ago