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AveGali [126]
3 years ago
10

I need help with this equation. I'm not that smart so I can't figure it out-

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

x = 0

Step-by-step explanation:

In order to solve for x, first combine both fractions on the left

To add 4x-2/8 + 3+x/4 first find the least common denominator of 8 and 4

It's 8 so multiply the numerator and denominator of 3+x/4 by 8, you would get:

8x+24/32

Multiply 4x-2/8 by 4, you will get:

16x-8/32

Now you can add 16x-8/32 + 8x+24/32, you would get:

24x+16/32

Now you can start to solve for x

Your new equation is 24x+16/32 = 1/2

To solve for x, first multiply diagonally, then solve like a regular equation.

Multiply 24x+16 by 2 to get 48x+32

Then multiply 32 by 1 to get 32

Your new equation is 48x+32=32

Now subtract 32 by 32 to get 48x=0

Now divide 48 by 0 to get x=0

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Can someone please help me with this math question .
Alona [7]

No, Yes, No, Yes

using the laws of exponents

(1)

(4^{3})³ = 4^{9}

4³ × 4³ = 4^{6}

4^{9} ≠ 4^{6} → No

(2)

(3^{4})^4 = 3^{16}

3^{8} × 3^{8} = 3^{16} → Yes

(3)

18^{8} = (6 × 3 )^8 = 6^{8} × 3^{8} ≠ 6^{4} × 3^{4} → No

(4)

20^{3} = (4 × 5 )³ = 4³ × 5³ → Yes




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3 years ago
What is the measure of 2?
Fiesta28 [93]

Answer:

Value of x:

{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\  { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7

Finding m‹2 :

{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}

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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

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Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

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