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ch4aika [34]
3 years ago
6

Can you guys help with me

Mathematics
2 answers:
andrezito [222]3 years ago
6 0

Answer:

x=8

Step-by-step explanation:

Anika [276]3 years ago
4 0

Answer:

x=8

Step-by-step explanation:

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BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

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PLZ HELP!!!! WILL MARK BRAINLIEST!!!!
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Answer:

2a^{3} b^{5

Step-by-step explanation:

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<h3>Solution : </h3>

\bf Speed = \dfrac{\dfrac{4}{5}}{\dfrac{1}{6}}

\bf Speed = \dfrac{4}{5} \times \dfrac{6}{1}

\Large \boxed{\bf Speed = \dfrac{24}{5}}

\pink{\bf So, \: the \: answer \: is \: \dfrac{24}{5} \: miles \: per \: hour}

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