Answer: Norm Alpina did better with z-score 0.79
Step-by-step explanation:
Z score formula = (raw score - mean) / standard deviation
For Jack Hartig,
score = 4; mean = 2.9; standard deviation = 2.1
Hence, Z score = (4 - 2.9) /2.1
= 1.1/2.1
= 0.52
For Norm Alpina,
score = 8; mean = 6.5; standard deviation = 1.9
Hence, Z score = (8 - 6.5) /1.9
= 1.5/1.9
= 0.79
Relatively, Norm Alpina did better for having Z score 0.79
Answer:
5 times larger
Step-by-step explanation:
5*10^5 = 500,000
1*10^5 = 100,000
500,000/100,000 = 5
Answer:
0.9544
Step-by-step explanation:
P(-2 < Z < 2) means that Z has mean 0 and standard deviation 2.
P(−2 < Z < 2) = F(2) - F(-2)
Using the Z - table,
F(2) = 0.9772
and F(-2) = 0.0228
Thus,
P(−2 < Z < 2) = 0.9772 - 0.0228 = 0.9544
This means that data within two standard deviation is 95%.
I got -19/655 and i know for sure this isnt the correct answer.
First thing to do is to solve each of these for y. The first one is y=-4x-3; the second one is y=4x-21; the third one is y=4x+21; the fourth one is y=-4x+3. From that you can tell the positive slopes are found in the second and third equations. Those are the ones we will test now for the point (3, -9). y=-9 and x=3, so let's fill in accordingly. The second equation filled in is -9=4(3)-21. Does the left side equal the right when we do the math? -9=12-21 and -9=-9. So the second one works. Just for the sake of completion, let's do the same with the third: -9=4(3)+21. Does -9=12+21? Of course it doesn't. Our equation is the second one above, y+9=4(x-3).
