Answer:
import java.util.Arrays;
public class swap{
public static void main(String []args){
int [] arr = {2,4};
swapValues(arr);
}
public static void swapValues(int[] values){
int temp;
System.out.println(Arrays.toString(values));
temp=values[0];
values[0]=values[1];
values[1] =temp;
System.out.println(Arrays.toString(values));
}
}
Explanation:
In the program above, we created the method swapValues that receives an array of integers as parameters. in the method definition, we created a temp variable that is used to swapp the element at index 0 and index 1. Java's Arrays.to string method is used to print the array before and after the swap.
Geostationary satellites have a high propagation delay.
Answer:
The solution code is written in Java.
- public class Main {
- public static void main(String[] args) {
- System.out.print("Please enter a number: ");
- Scanner console = new Scanner(System.in);
- int n = console.nextInt();
- calculateSum1(n);
- calculateSum2(n);
- calculateSum3(n);
- calculateSum4(n);
- }
- public static void calculateSum1 (int num){
- int sum1 = 0;
- for(int i=1; i <= num; i++){
- sum1 += i*i*i;
- }
- System.out.println("Sum 1 : " + sum1);
- }
- public static void calculateSum2 (int num){
- int sum2 = num * num * (num + 1) * (num + 1) / 4;
- System.out.println("Sum 2 : " + sum2);
- }
- public static void calculateSum3 (int num){
- int sum3 = 0;
- for(int i=1; i <=num; i++){
- sum3 += i;
- }
- sum3 = sum3 * sum3;
- System.out.println("Sum 3 : " + sum3);
- }
- public static void calculateSum4 (int num){
- int sum4 = (num * (num + 1) * (2*num + 1)) / (4+2);
- System.out.println("Sum 4 : " + sum4);
- }
- }
Explanation:
Firstly we create four different methods that calculate the sum of the first n cubes in different ways (Line 13 - 43).
This is important to understand the concept of operator precedence to work out the different ways of summation.
For example, The operator * and / will always have higher precedence than +.
On another hand, any expression enclosed within the parenthesis will have highest precedence and therefore the value will be evaluated prior to others.
This is also important to understand the expression evaluation will always start from left to right.
Answer:
All of given terms are Categories of Wireless networks.
Explanation:
Wireless networks as obvious from name are the networks having no means of physical medium such as cords, wires or cables. This gives the advantage of mobility and extension of the applications to different parts of building, block and even anywhere in word. Wireless network can be divided into four basic categories in order to differentiate between there quality and range:
<u>Category Coverage</u>
- Wireless Personal Area Network (WPAN) | Within One person
- Wireless Local Area Networks (WLAN) | Within a building
- Wireless Metropolitan Area Networks (WMAN) | Within a city
- Wireless Wide Area Networks (WWAN) | Worldwide
i hope it will help you!
The intercept of a graph is the point where the graph crosses the axes of the graph.
The interpretation of the c-intercept is: <em>in 1996, the global wind power capacity was approximately 7 gigawatts.</em>
On the graph (see attachment), we have the following observations
- The vertical axis represents the global wind power capacity (i.e. the c-axis)
- The horizontal axis represents the years since 1996 (i.e. the t-axis)
So, the c-intercept is the point that crosses the vertical axis.
From the graph, the curve crosses the c-axis at c = 7, and t = 0 (i.e. years = 1996)
Hence, the interpretation of the c-intercept is: <em>in 1996, the global wind power capacity was approximately 7 gigawatts.</em>
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Read more about intercepts at:
brainly.com/question/3334417
