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3 years ago

HELP PLEASE!!!!

Computers and Technology

1 answer:

denis23 [38]3 years ago

5 0

Answer:

1100 ; 11000 ; 110000 ; 1100000

Explanation:

Converting the following decimals to binary :

2__12

2__6 r 0

2__3 r 0

2__1 r 1

___0 r 1

12 = 1100 base 2

2.)

2__24

2__12 r 0

2__6 r 0

2__3 r 0

2__1 r 1

___0 r 1

24 = 11000 base 2

2__48

2__24 r 0

2__12 r 0

2__6 r 0

2__3 r 0

2__1 r 1

___0 r 1

48 = 110000 base 2

2__96

2__48 r 0

2__24 r 0

2__12 r 0

2__6 r 0

2__3 r 0

2__1 r 1

___0 r 1

96 = 1100000 base 2

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Explanation:

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3 years ago

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Write a SELECT statement that returns one row for each customer that has orders with these columns: The email_address from the C

bazaltina [42]

Answer:

Please find the attachment files of the queries:

Explanation:

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3 years ago

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7 0

3 years ago

Suppose we have a dictionary called grades as shown below:

mihalych1998 [28]

Answer:

import statistics as st # importing statistics package to calculate mean as st.

grades = {"John": [87,90,86.8], "Mary": [78, 81.5, 88.6],"Susan":[45,67,76]}

for key,value in grades.items():#iterating over the dictionary

average_score=st.mean(value)#calculating the mean of every student

gr="" empty string to store the grades

if average_score>=90: # nested if else if and statements for the grades in gr

gr="A"

elif average_score>=80.0 and average_score<90.0:

gr="B"

elif average_score>=70.0 and average_score<80.0:

gr="C"

elif average_score>=60.0 and average_score<70.0:

gr="D"

else :

gr="F"

print(str(key)+" "+str(average_score)+" "+str(gr)) #printing grades of every student.

Output:-Mary 82.7 B

John 87.93333333333334 B

Susan 62.666666666666664 D

Explanation:

1.In this program we are iterating over the dictionary grades.

2.Storing and calculating the mean of the scores of every student us statistics package.

3.Storing the grade in string gr and updating the gr according to the mean score

4.After that printing the grade of the student with their name and mean score.

6 0

3 years ago