Question

Hi. I need help with these See image for question Answer no 8 ,9 and 10

Answer 1

Answer:

• 8) 4 + 2q²/p² - 4r/p + r²/p²
• 9) (3/4, -9/4)
• 10) (3/8, 41/16)

Step-by-step explanation:

8. ============

Given

• α and β are roots of px² + qx + r = 0

The sum of the roots is α + β = -q/p, the product of then roots αβ = r/p

• (2 + α²)(2 + β²) =  
• 4 + 2(α² + β²) + (αβ)² =
• 4 + 2((α + β)² -2αβ) + (αβ)² =
• 4 + 2((-q/p)² - 2r/p) + (r/p)² =
• 4 + 2q²/p² - 4r/p + r²/p²

------------------------------

9. ============

Given function

• y = 2x² - 3x - 1

The minimum point is reached at vertex

The vertex is:

• x = -b/2a
• x = -(-3)/2*2 = 3/4

The corresponding y-coordinate is:

• y = 2(3/4)² - 3(3/4) - 1 = 9/8 - 9/4 - 1 = 1/8(9 - 18 - 9) = - 18/8 = - 9/4

So the point is:

• (3/4, -9/4)

---------------

10. ============

Given function

• y = 2 - 3x - 4x²

The maximum is reached at vertex

The vertex is:

• x = -b/2a
• x = -(-3)/2(-4) = -3/8

The corresponding y-coordinate is:

• y = 2 - 3(-3/8) -4(-3/8)² = 2 + 9/8 - 9/16 = 1/16(32 + 18 - 9) = 41/16

So the maximum point is:

• (3/8, 41/16)