All categories

3 years ago

A parallelogram has

Mathematics

2 answers:

exis [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Yes it is

Sergio [31]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

because a square has two pairs of parallel sides, four right angles, and all four sides are equal. It is also a rectangle and a parallelogram. A rhombus is defined as a parallelogram with four equal sides.

also can u plz mark me as brainliest ;w; ^w^

You might be interested in

Pls help guys ur my only hope pls i need a good grade pls help plssssssss

juin [17]

Answer: The answer is B, 6 1/2

Step-by-step explanation:

6+5= 11

1/2+1/2= 1

11+1= 12

12-3=9

7 0

2 years ago

Read 2 more answers

Are the expressions equivalent? 10(x + 2); 10x + 5

lutik1710 [3]

Answer: yes, indeed it is i forgot how it is but it is

7 0

2 years ago

I need help please (;´༎ຶٹ༎ຶ`)

spayn [35]

The dude on top of me is correct

7 0

3 years ago

PLEASE HELP ME I BEG YOU!?

weeeeeb [17]

The answer to question 5 is D.5 and the answer to question 9 is (-2,-6)

3 0

3 years ago

Read 2 more answers

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago