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3 years ago

which number is a solution of the inequality c>5? Use the number line to help answer the question.

Mathematics

1 answer:

cricket20 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

brainly.com/question/22157981

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How do you solve -2+6(-6x+6)?

Natali5045456 [20]

Answer: −36x+34

Step-by-step explanation:

Equation: −2+6(−6x+6)

Step 1. distribute the equation:

−2+(6)(−6x)+(6)(6)

−2+−36x+36

Step 2. Finally combine like terms:

−2+−36x+36

(−36x)+(−2+36)

−36x+34

Final Answer:

−36x+34

Hope I could help! :)

4 0

3 years ago

Write 0.87 as a fraction in simplest form.

TEA [102]

Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1

Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's

Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100

N / D = 87 / 100

Simplifying our fraction

= 87/100

<span>= 87/100</span>

8 0

4 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago

Please solve and explain how. Photo attached

geniusboy [140]

Answer:

Step-by-step explanation:

$\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}$

multiply by $\frac{k^2-2k}{1}$ on each side

$2=k^2-2k-1$

add 1 on both sides $3=k^2-2k$

make it equal 0

$0=k^2-2k-3$

Factor

$(k-3)(k+1)$

answer is 3 and -1

7 0

3 years ago

A computer manufacturer shipped a total of 50 machines to its two warehouses, one in west and one in east. It cost 20$ per machi

Natalka [10]

E + w = 50.....w = 50 - e
25e + 20w = 1090

25e + 20(50 - e) = 1090
25e + 1000 - 20e = 1090
25e - 20e = 1090 - 1000
5e = 90
e = 90/5
e = 18 <=== the east got 18

w = 50 - e
w = 50 - 18
w = 32 <=== the west got 32

5 0

3 years ago

Read 2 more answers