Answer:
The student must score 79.75% to be invited to join the honors program.
Step-by-step explanation:
Let <em>X</em> denote the score of a freshman in the entrance exam.
It is provided that the average test score is 78%, with a standard deviation of 11%.
It is provided that the top 10% being offered admission to the university's honors program.
Let <em>x</em> denote the score eligible for being offered admission to the university's honors program.
Then, P (X ≤ x) = 0.90.
Then P (Z < z) = 0.90.
The corresponding <em>z</em>-score is, 1.28.
*Use a <em>z</em>-table<em>.</em>
Compute the value of <em>x</em> as follows:
Thus, the student must score 79.75% to be invited to join the honors program.