Remember that if f and g are inverses of one another, then
f(g(x)) = g(f(x)) = x
1/2. Take a = 0 and b = 1 (or any non-zero number) so that
f(x) = x + 0/1 ⇒ f(x) = x
If g is to be an inverse of f, we need
g(f(x)) = g(x) = x
so that c = 1 and d = 0.
3. With f(x) = x + a/b and g(x) = cx - d, we have
g(f(x)) = g(x + a/b) = c (x + a/b) - d = cx + ac/b - d
and of course, with a,b,c,d as before, we get g(f(x)) = x.
4. This would be a very uninteresting graph for the example I've cooked up here, just containing the line y = x...
7 x 1/1 = 7 you can also substitute 1/1 with 2/2 ,3/3, 4/4, ext.
hope this helps you have a great day
quotient =27
remainder =0
A) She went to the club 8 times in march, and every time she visits, she has to pay $8.25. So you do $8.25 * 8, and you get $66, which is higher than the flat rate of $35.50, hence they will use that value as it is greater.
So the answer is $66.
B) If she doesn't want to pay more than the flat rate, she needs to go the club a certain number of times so it doesn't exceed $35.50. You can work out the nearest value by doing 35.50 divided by 8.25 to find out how many times she can go. This gives you 4.3 something, but you cant go 4.3 times, so the nearest value would be rounded down to make sure it's under $35.50, hence, she can go a maximum of 4 times.
She can go the club a maximum of 4 times in April.
