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qwelly [4]
3 years ago
8

Which letters Shown below on the number line also have their opposites labeled? (A- A and D) (B- B and C) (C- A B and C) (D- B C

and D)

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

try number 4 I thinks its that one or number 1

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Ms.smith has 28 sixth graders and 35 seventh graders for math. She wants to break the two grades into identical groups without a
Svetradugi [14.3K]
There will need to be 9 groups of 7
5 0
3 years ago
Read 2 more answers
4(n-1)+2 = -23 +7n
liubo4ka [24]

Answer:

<h2><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em></h2>

Step-by-step explanation:

4(n-1)+2 = -23 +7n

=> 4n - 4 + 2 = - 23 + 7n

=> 23 - 4 + 2 = 7n - 4n

=> 21 = 3n

=  > n =  \frac{21}{3}

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

6 0
3 years ago
Which equation has the same solution as 2x^2+x-3
inn [45]
2x² + x - 3
2x² - 2x + 3x - 3
2x(x) - 2x(1) + 3(x) - 3(1)
2x(x - 1) + 3(x - 1)
(2x + 3)(x - 1)
7 0
3 years ago
Eight times the reciprocal of a number equals 4 times the reciprocal of 2. find the number
uysha [10]

Answer:

The number is 4

Step-by-step explanation:

Let the number  = 'x'

Reciprocal of 'x' = 1/x

Reciprocal of 2 = 1/2

8 times the reciprocal of 'x' = 8*\frac{1}{x}\\

8*\frac{1}{x}= 4* \frac{1}{2}\\\\8*\frac{1}{x}= 2\\

Now multiply both sides by x

8*\frac{1}{x}*x = 2*x\\\\8 = 2x

Now divide both sides by 2

\frac{8}{2}=\frac{2x}{2}\\\\4 = x

x = 4

4 0
3 years ago
Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete
BigorU [14]

Linear pair angles, which are angles that together form a straight line are

supplementary angles.

The one that completed the proof incorrectly is <u>Becky</u>.

Reasons:

The two column proof is presented as follows;

Statement {}                                                             Reason

1. Segment GH intersects segment AB at K {}     1. Given

2. m∠AKG + m∠HKB = 180°    {}            2.Definition of Supplementary Angles

m∠GKB + m∠HKB = 180°

3. m∠AKG + m∠HKB = m∠GKB + m∠HKB      {}  3. Substitution property

4. m∠AKG = m∠HKB     {}                                      4. Subtraction Property

The difference between Angie's Proof and Becky's Proof is in Statement 2.

  • Angie states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by definition of Supplementary Angles

  • Becky states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by Angle Addition Postulate

Becky's proof is incorrect because the measure of angles  m∠AKG and

m∠HKB and m∠GKB and m∠HKB are not given, therefore, the use of the

reason of Angle Addition Postulate in statement 2. is incorrect.

Learn more here:

brainly.com/question/13204208

8 0
3 years ago
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