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4 years ago

Explain how you used the bar model in exercise 2 to find the problem

Mathematics

1 answer:

PolarNik [594]4 years ago

8 0

This question isn't relevant to this site.

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What is the probability that two different colored marbles are drawn, given that the first marble drawn is red?.

inessss [21]

Answer:

what are the color of the marbles that are not red?

Step-by-step explanation:

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2 years ago

Victoria combined 2 3/4 cups of granola and 1 1/4 cups of raisins to make trail mix. How much trail mix did she make?

Alenkinab [10]

2 and 3/4 + 1 and 1/4 = 3 and 4/4 = 4

5 0

3 years ago

Read 2 more answers

In the diagram shown, line m is parallel to line n. Robert says that ∠2 and ∠7 are supplementary angles. Is he correct? Why or w

bekas [8.4K]

Robert is not correct because in order for it to be supplementary the angles have to be consecutive interior

6 0

3 years ago

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers

dalvyx [7]

Answer:

4 pitchers

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

step 1

Find the volume of the cylinder with height 9 inches and radius r

substitute the given values

$V_1=\pi r^{2}(9)$

$V_1=9\pi r^{2}\ in^3$

step 2

Find the volume of the cylinder with height 9 inches and radius 2r

substitute the given values

$V_2=\pi (2r)^{2}(9)$

$V_2=36\pi r^{2}\ in^3$

step 3

we know that

The volume of the cylinder 1 can fill a certain pitcher,

The volume of the pitcher is the same that the volume of cylinder 1

therefore

the number of pitchers that can be filled by the second cylinder is equal to divide the volume of the second cylinder by the volume of the first cylinder

$\frac{36\pi r^{2}}{9\pi r^{2}}=4\ pitchers$

3 0

3 years ago

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

4 years ago