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Lemur [1.5K]
4 years ago
9

Explain how you used the bar model in exercise 2 to find the problem

Mathematics
1 answer:
PolarNik [594]4 years ago
8 0
This question isn't relevant to this site.
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Simplify the expression
AlexFokin [52]

Answer:

B

Step-by-step explanation:

\frac{3+4\iota}{2+4\iota}=\frac{3+4 \iota}{2+4\iota} \times \frac{2-4 \iota}{2-4 \iota}\\=\frac{6 -12 \iota+8 \iota-16 \iota^2  }{4-16 \iota^2  }\\=\frac{ 6-4 \iota+16}{4+16}\\=\frac{22-4 \iota}{20}

5 0
3 years ago
A conductor needs 5 cellists and 5 violinists to play at a diplomatic event. to do this, he ranks the orchestra's 10 cellists an
DaniilM [7]
Ranking is very critical in this problem. Therefore, the most applicable mathematical theory is permutations.

Ranking possible for the cellists:
Needed cellists = 5
Total available cellists = 10
Possible number of rankings = 10P5 = 10!/(10-5)! = 30240

Ranking possible for the violinists:
Needed violinists = 5
Total available = 16
Possible number of rankings = 16P5 = 16!/(16-5)! = 524160

Therefore,
Ratio of rankings (cellists to violinists) = 30240/524160 = 3/52
3 0
4 years ago
Lauren ran for 45 minutes and traveled 3 miles. what is her rate per mile
Lady bird [3.3K]
I think that her rate per mile is 15 miniutes
5 0
3 years ago
Read 2 more answers
Henry had 15 quarters. He gave his sister 4 quarters. How much money does he have now??
telo118 [61]

Answer:

$2.75

Step-by-step explanation:

A quarter's value as placed on it by the U.S. Treasury Department is $0.25, or 1/4 of a dollar.

Henry had 15 quarters, in which he gives his sister 4: 15 - 4 = 11

Henry now has 11 quarters. Multiply 11 with 0.25: 11 x 0.25 = 2.75

Henry has $2.75

~

5 0
3 years ago
solve each equation. Round your answers to the nearest ten-thousandth. Show your work please. Part 2A​
Reika [66]

Answer:

16. x = 3.0822, -3.0822

17. x = 1.6432, -1.6432

18. x = 1, -1

Step-by-step explanation:

16. log5[(4x²+2)/8] = 1

(4x²+2)/8 = 5¹

4x² + 2 = 40

4x² = 38

x² = 38/4

x² = 19/2

x = +/- sqrt(19/2)

x = 3.0822, -3.0822

17. log7[(2x²-4)(5)] = 1

10x² - 20 = 7¹

10x² = 27

x² = 2.7

x = +/- sqrt(2.7)

x = 1.6432, -1.6432

18. log5[(2x²+8)/2] = 1

x² + 4 = 5¹

x² = 1

x = +/-1

4 0
3 years ago
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