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Lemur [1.5K]
4 years ago
9

Explain how you used the bar model in exercise 2 to find the problem

Mathematics
1 answer:
PolarNik [594]4 years ago
8 0
This question isn't relevant to this site.
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The spinner below is spun twice. What is the probability of the arrow landing on a 3 and then an odd number?
Mice21 [21]

Answer:

4/3

Step-by-step explanation:

6 0
3 years ago
if on a scale drawing 35 feet are represented by 25 inches, then a scale of 1/8 inch represents how many feet?
kirill115 [55]

Answer:

7/40 feet

Step-by-step explanation:

Solve using proportions:

\frac{25in}{35ft} =\frac{1/8 in}{?ft}

Find the scale factor by dividing the numerators 25 by 1/8.

25 ÷ 1/8 = 200   This is the common ratio

To get from the top left number to the top right number, you divide 25 by 200.

To get from the bottom left number to the bottom right number, you divide 35 by 200.

35 ÷ 200 = 0.175

1/8 of an inch represents 0.175 feet.

To find 0.175 in fraction form, reduce 35/200 to its lowest terms.

35/200 = 7/40

1/8 of an inch represents 7/40 feet.

8 0
3 years ago
Find the midpoint of a line segment with endpoints (4, -10) and (-8, 2).
pychu [463]

Step-by-step explanation: (-2,-4)

5 0
3 years ago
What is the answer for the equation (2+3x)4
balandron [24]

Answer:

8+12x

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help!! Find missing value for each quadratic function
Svetllana [295]

I'll do the first one to get you started. The answer is -3

=================================================

Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

------------

Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

1 = a*0^2 + b*0 + c

1 = 0a + 0b + c

1 = c

c = 1

------------

Plug in (x,y) = (-1,0) and c = 1

y = ax^2 + bx + c

0 = a*(-1)^2 + b(-1) + 1

0 = 1a - 1b + 1

a-b+1 = 0

a-b = -1

a = b-1

------------

Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

0 = 2b

2b = 0

b = 0/2

b = 0

------------

If b = 0, then 'a' is...

a = b-1

a = 0-1

a = -1

------------

In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

------------

The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

y = -3


3 0
3 years ago
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