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Phantasy [73]
3 years ago
14

Find the missing angle

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0

Answer:

160°

Step-by-step explanation:

Leya [2.2K]3 years ago
3 0

Answer:

160°

Step-by-step explanation:

corresponding angles

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How do I solve this problem
aleksley [76]
The first blank is 121 and the second blank is 144
8 0
4 years ago
Please please help me
Lina20 [59]

Answer:

D

Step-by-step explanation:

Used calculator and got 0.0782776601

6 0
3 years ago
Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
4 years ago
What is the answer to 3/7 × £28
Alona [7]
The answer is 12! :)
5 0
3 years ago
Read 2 more answers
What adds to 10 and multiplies to -300
Anton [14]
X+Y=10
XY=-300

Solve for one of the variables

X=10-Y

Plug into the other equation

Y(10-Y)=-300

Now, you have a quadratic...

-y²-10y+300=0

I would multiply everything by -1, so there's no coefficient on y²

y²+10y-300=0

And solve...

-10±√(100-4(-300))
----------------------------
2

Y=-5±5√(13)

Plug back onto original equation...

X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)

Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.
8 0
4 years ago
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