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3 years ago

Which two transformations were preformed

Mathematics

1 answer:

Delicious77 [7]3 years ago

7 0

a stretch by 3 and a rotation

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It is not a function because both (2, 2) and (2,−2) have the same x-coordinate. It is a function because both (2, 2) and (2,−2)

olya-2409 [2.1K]

Answer:

It is not a function because both (2,2) and (2,-2) have the same x-coordinate.

Step-by-step explanation:

To be a function for the same x value there should NOT be two different y values.

So, in (2, 2) and (2,-2)

For the same x value 2, there are two different y values 2, -2.

So, this is not a function.

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2 years ago

У= 3х-5<br> у = 3х+12<br> Please help ASAP for my lil sister

exis [7]

Answer:

Step-by-step explanation:

The equation is undefined.

4 0

2 years ago

Easy question Give a formula used for finding the area of a square. Then use the formula to find the area of a square with a sid

Alik [6]

A=s^2

A=6.3^2

(A=6.3x6.3)

And your answer would be:

A=39.69cm^2

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3 years ago

How to find the volume of a pyramid

lbvjy [14]

$V=\dfrac{1}{3}BH\\\\B=9\cdot6=54\ (in^2)\\H=7\ in\\\\subtitute\\\\V=\dfrac{1}{3}\cdot54\cdot7=18\cdot7=126\ (in^3)$

Answer: a. 126 in³.

6 0

2 years ago

This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is

$\displaystyle\sum_{n=1}^6\frac1{2^n}$

4 0

2 years ago