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ivanzaharov [21]
3 years ago
13

Solve for x !!!!!!!!!!!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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Find the value of x. <br> A. 2 <br> B. 3 <br> C. 4 <br> D. 5
masya89 [10]
The correct answer is three.
7 0
3 years ago
13 is 26% of what number​
Marina CMI [18]

Answer:

50

Step-by-step explanation:

6 0
3 years ago
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If you subtract 12 from my number and multiply the difference by - 5, the result is -90." What is Sara's number?​
Natali [406]

Answer:

30

Step-by-step explanation:

Do the steps in reverse

-90 divided by -5 = 18

18 + 12 = 30

Your answer is 30

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5 0
3 years ago
Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,
brilliants [131]

The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

<u>The lost weight of a pair of boys is 120 kg</u>

Reasons:

Let <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em><em> </em>represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

_nC_r = \dfrac{n!}{r! \cdot (n - r)!}

Which gives;

_4C_2 = \dfrac{4!}{2! \cdot (4 - 2)!} = 6

₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

a + c = 112

a + d = 113

b + c = 118

b + d = 121

c + d = Lost weight

  • c + d = Lost weight

a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

Which gives;

c + d = 230 - (110) = 120

The lost weight = c + d = 120

  • <u>The lost weight = 120 kg</u>

Learn more here:

brainly.com/question/12974932

6 0
3 years ago
Read 2 more answers
Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0
3 years ago
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